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2x^2+9x-188=0
a = 2; b = 9; c = -188;
Δ = b2-4ac
Δ = 92-4·2·(-188)
Δ = 1585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{1585}}{2*2}=\frac{-9-\sqrt{1585}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{1585}}{2*2}=\frac{-9+\sqrt{1585}}{4} $
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